0=x^2+6x-476

Solution for 0=x^2+6x-476 equation:

0=x^2+6x-476

We move all terms to the left:

0-(x^2+6x-476)=0

We add all the numbers together, and all the variables

-(x^2+6x-476)=0

We get rid of parentheses

-x^2-6x+476=0

We add all the numbers together, and all the variables

-1x^2-6x+476=0

a = -1; b = -6; c = +476;
Δ = b2-4ac
Δ = -62-4·(-1)·476
Δ = 1940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1940}=\sqrt{4*485}=\sqrt{4}*\sqrt{485}=2\sqrt{485}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{485}}{2*-1}=\frac{6-2\sqrt{485}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{485}}{2*-1}=\frac{6+2\sqrt{485}}{-2}
$